‘Live’ posting style (December the 20th UPDATE: see the comment below, where I put a link to ‘Time distortions estimations’).
This post is part of the last update, I have just done, for the previous post of this series, into which I modified a little some text, in order to be better understood, if you already read it, go on reading after the sentence ‘Happy Christmas (again) !’, where I will be commenting what happens today at orto, which I am waiting for, so, read the updates for this also.
‘… without the ground, the Sun and the grids: azimuthal, and equatorial are visible, if you take a look into the degrees numbers for the azimuthal grid on the right border, in orange, you will see the Sun is 25º more or less from the 0º that is the value for the horizon, so according to Stellarium, it should have risen one hour and twenty minutes later than the time in the image: 06:37:43 (UTC + 1), and that is 07:57’
I put it like this for the sake of clarity, indeed it is not exactly like that, but it is much more easy to understand the concept of rising astra like that, because of the grid’s disposition. Look at this edited yesterday’s image crop below, where I (who is not an astronomer [see grammar note afterwards 🙂 ]) put some lines, and read below the explanations.
The Sun’s sunrise was little less than two hours from orto, this is the time when its perimeter (more or less a circumference) touches the line of the horizon, and that is the time to start measuring dawn, which, at this latitude (distance from the Earth’s equator) yesterday’s date, December the 9th 2015, should have lasted 20 clock minutes at most, until day arrives, when stars are not visible at all until next night comes.
Think of it as taking either of the two blue lines I put in the crop (take on account it is not a fine-tuned drawing, as others I did, so distances are approximate [in addition of me not being an astrophysicist).
As the distance in either of the two grids are near one another, I explained it with the orthonormal (= 90º arc circumference) grid, in orange, because it is much more easy to understand, only having to count the 10º lapse for every orange line ‘parallel’ to horizon’s line, which is that which joins N and E, in the image.
‘Who‘ is a relative pronoun, it can be translated in Spanish as “que”, “quien”, “quienes”, and its Spanish translations can take or take not the Spanish tilde sign, depending this on the sentence type: if it is a question, the translation takes the tilde, if it is not, it doesn’t, so, in English, ‘who’ can be either for singular, or plural, and take the verb’s corresponding personal pronoun: I, you, he, she, it, we, they, in either of the forms depending on the voice (passive, active), the mode (indicative, subjunctive), or the sentence itself.
So, yesterday I put the little Spanish joke text: “Lo que diga la rubia”, translation to English, that would be: ‘Do as the blond one says’, and added this part between braces, being then: “Do as the blonde one (me, who by the way, am dark-haired…) says”.
Well… it is not well written, according to English grammar rules, I should have written it like this: “Do as the blonde one (me, who by the way, is dark-haired…) says”.
But I put it with the ‘am’ form for ‘to be’ present simple active indicative form, in order not to be mistaken with somebody else by not English advanced speakers.
So, I do apologize for the grammar misleading I should have spread on my readers’ minds…
Happy Christmas (again) !
Stellarium, December the 10th 2015
These two images are Stellarium snapshots made at the hours (06:11:ss, very near to yesterdays hour at 06:09:ss (UTC + 1)) you can see at the bottom of them, to be peer-revised with those of yesterday’s snapshots.
In the event that sunrise starts earlier today, than it did yesterday (07:57 <-> 8:10 -> 8:15), this would mean, we are now in January the 28th (approximately), and thus, the true mid-day value I observed yesterday, would have to be recalculated (which I’ll do if it is sunny as to see it clearly) as 13:23 + 12 = 13:35 p.m. , Spanish hour (= UTC + 1) winter time, and there would be a shift of twenty (|-8| + |12| = 20, whose zero position would have to be determined), clock minutes (+-1 min) with what I see were Polaris should be.
And in that case, the displaced value of the Earth in its elliptical trajectory around the Sun, would be of 21 days to New Year’s Eve, the 31st of December, plus, 27 days, to distorted-today, January the 28th, ~=48 days of 24 hours.
Now it’s 08:04 and it is already day.
Adding (if so) 8 minutes for lemniscata’s 08:12 a.m., 33 minutes in advance for the timetable 08:45 a.m. should be. Much longer than dawn would take, so if you are astrophisicists, see what you can do about it.
I’ll wait till it’s clearly day to anyone (the average Joe).
I think now it is clear to everyone 08:30 a.m. (UTC + 1) winter time.
I’ll tell what happens at mid-day if visibility conditions are good, later.
I will tell you what happened today, after I make some drawings and then I’ll publish my calculi and estimations for true mid-day today, December the 10th 2015, in the next series post ‘Time Shift (V)’, but as a quick and not to be taken as an exact value, because of what I will explain in (V) post of this series later, and after publishing a humorous post in the ‘Astunglish’ section (and also in ‘Pulpito de colores’), which you can find as a sub-page of ‘Asturias’ page, either by clicking on ‘My blog’s pages’ widget, or by browsing the ‘Menu’ tool, with its dropdowns.
… but as a quick and not to be taken as an exact value, I tell you it was at 13:15:10 p.m. , according to my observations, but don’t be so fast in any case, because the air’s pollution, and misty atmosphere, didn’t draw so clear a line, as other days, so, please, WAIT until I deploy the explanation, and go on checking yourselves.
I’ll start it introducing this excerp I have just corrected:
… In the event that sunrise starts earlier today, than it did yesterday (07:57 <-> 8:10 -> 8:15), this would mean, we are now in January the 28th (approximately), and thus, the true mid-day value I observed yesterday, would have to be recalculated (which I’ll do if it is sunny as to see it clearly) as 13:23 + 12 = 13:35 p.m. , Spanish hour (= UTC + 1) winter time, and there would be a shift of twenty (|-8| + |12| = 20, whose zero position would have to be determined), clock minutes (+-1 min) with what I see were Polaris should be.
And in that case, the displaced value of the Earth in its elliptical trajectory around the Sun, would be of 21 days to New Year’s Eve, the 31st of December, plus, 27 days, to distorted-today, January the 28th, ~=48 days of 24 hours…
Wait until I write the explanations.